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Its easy just apply formula of a^3 + b^3 =(a+b)^3 -3ab(a+b)
applying this
(x+y)^3 - 3xy(x+y) + 15xy -125
by putting the value of x+y=5
the answer will be equal to zero
0 0 0
please mark my answer as the best
(x+y) ^{3} =5 ^{3}  \\ x^{3} +y ^{3} +3xy(x+y)=125 \\ substitue  (x+y)  value i  n the equation  ans u will get is 0
0 0 0
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