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The sum of the age of a father and his son is 45years five years ago the product of their ages was 4 times the fathers age at that time find their present

f + s = 45 (f-5)(s-5)=4(f-5) ---- Substitute for "f" and solve for "s": f = 45-s (45-s-5)(s-5) = 4(45-s-5) ---- Divide both sides by 45-s-5 to get: s-5 = 4 s = 9 (son's age now) ---- Solve for "f": f+9 = 45 f = 36 (father's age now)

Let the father's and son's age be x and y respectively. From the question : x+y=45. 5yrs ago the product of their ages: (x-5)(y-5). it was = 4(x-5). ∴(x-5)(y-5)=4(x-5) ∴y-5=4 &y=9 we know that x+y=45. ∴x+9=45 ∴x=36. ∴their present ages are: Father:36yrs. Son:9yrs.