# The sum of the age of a father and his son is 45years five years ago the product of their ages was 4 times the fathers age at that time find their present ages

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by satya4

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by satya4

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The Brainliest Answer!

(f-5)(s-5)=4(f-5)

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Substitute for "f" and solve for "s":

f = 45-s

(45-s-5)(s-5) = 4(45-s-5)

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Divide both sides by 45-s-5 to get:

s-5 = 4

s = 9 (son's age now)

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Solve for "f":

f+9 = 45

f = 36 (father's age now)

From the question :

x+y=45.

5yrs ago the product of their ages:

(x-5)(y-5).

it was = 4(x-5).

∴(x-5)(y-5)=4(x-5)

∴y-5=4

&y=9

we know that x+y=45.

∴x+9=45

∴x=36.

∴their present ages are:

Father:36yrs.

Son:9yrs.

hope it helps and pls mark this as best answer :)