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The radii of two circles are 8 cm and 6 cm respectively find the radius of the circle having are equal to the sum of the areas of the two circles



Area of first circle= \pi
                            = \pi *64=64 \pi
Area of second circle= \pi
                                   = \pi *36=36 \pi
Sum=100 \pi
Area of final circle=100 \pi
100 \pi = \pi
∴Radius of required circle is 10cm

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radii of first circle=8cm
area of first circle=πr² =π(8)²=π64 cm²
radii of second circle =6cm
area of second circle=πr²=π(6)²=π36cm²
Sum of two circles=π64+π36=π[100] cm²
now,area of sum of two cirlces=100π=πr²
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plz mark brainlest
Its wrong
r=10cm not 10pie
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