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A box contains cards bearing numbers 6 to70. If one card is drawn at random then find the probability that it bears (a) a one digit number (b) a number

divisible by 5


A)P(that it bears a one digit number)= 4/64
b)p(a number divisible by 5)=12/64
0 0 0
excuse me but the 2nd one is wrong , please recheck
there are 13 probable events
Here is your solution , sorry for the bad writing
0 0 0
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