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In figure, ABC is a triangle ,D is the mid-point of AB ,P is any point on BC. Line CQ is drawn parallel to PD to intersect AB at Q. PQ is joined .Show that

ar (ΔBPQ) = ½ ar (ΔABC)


if two triangles lie on the same base and between the same parallels then the area is same here we can say that DP is a median therefore median divides anything into two equal parts
there area of BPQ = 1/2 area of ABC
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