Red light, however bright it is, cannot produce the emission of electrons from a clean zinc surface. But even weak ultraviolet radiation can do so. Why? X-rays of wavelength ‘λ’ fall on photosensitive surface, emitting electrons. Assuming that the work function of the surface can be neglected, prove that the de-Broglie wavelength of electrons emitted will be .

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Answers

2016-02-15T16:40:58+05:30
 The frequency of red light is less than the threshold frequency of zinc surface. Hence, it cannot cause photoelectric emission from zinc surface, whatever may be its intensity. The frequency of ultraviolet radiation is greater than the threshold frequency of zinc surface. Hence, even weak ultraviolet radiation can cause photoelectric emission. 
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