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A toroidal solenoid with air core has an average radius of 15 cm, area of cross-section 12 cm2 and has 1200 turns. Calculate the self-inductance of the

toroid. Assume the field to be uniform across the cross-section of the toroid.


The self inductance of a toroidal solenoid is given by L=μ0N2A2πr Here, N = number of turns A = area of cross-section r = average radius ∴L=4π×10-7×12002×12×10-42π×15×10-2 =230.4×10-5 H
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