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The number is 93 9+3=12 93-54=39 hence the number gets reversed when 54 is subtracted from 93. ( I found this by trial and error method )

let digit at tens place=x and at one's place=y no.= 10x + y x+y =12 10x +y - 54=10y +x solve the two equations acoordingly and you get the answer as 93 this is the logic of the program

Let the digit of unit place=x and digit of 10th place=y so, number is (x+10y) after reversing of digit number will be (y+10x) a/q, x+y=12 ------------EQN(1) now, (x+10y)-54=(y+10x) or, -9x+9y=54 or, x-y=-6 --------EQN(2) on adding EQN(1) & (2) 2x=6 or, x=3 put the value of x in (1) 3+y=12 or, y=9 therefore number will be (x+10y)=(3+10*9)=93