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Perimeter = 4 a = 32 => side = 8m diagonal c = 10m to find other diagonal d. Then area = c d / 2 cost of painting both sides = 2 * (c d / 2) * 5 Rs

In a Rhombus, c² + d² = 4 a² and c² - d² = 4a² cos Ф so d² = 4 * 8² - 10² = 156 d = 2 √39 m Cost = 100 √39 Rs.

Perimeter-32m Diagonal-10m Cost per sq.m- Rs.5 One side= 32/4=8 (Half the other diagonal)=Square route of (8^2-5^2) = Square route of (64-25) = Square route of 49 =7m Other diagonal=7*2=14m Area of Rhombus= (10*14)/2 =70sq.m Cost to paint = 70*5 =Rs.350