Answers

2016-02-15T21:58:36+05:30
Let a circle with center O of radius OA = 10 cm.
and length of chord = AB = AM + MB
and OM divides the into two equal parts.
i.e, AM = MB 
therefore AB = 2.AM
given,

distance between center and chord = OM = 5 cm.
from ΔOMA 
    (OA) ² =  (AM)² + (OM)²
⇒ 10² = (AM)² + 5²
⇒ 100 = (AM)² + 25 
⇒ (AM)² = 100 - 25 = 75
∴  AM = √75 = 5√3 cm
Therefore length of chord) = AB = 2.AM = 2×5√3 =10√3 cm
0