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Two men on either side of a temple 75m high observe the angles of elevation of the top of the temple to be 30 0. and 60 0 respectively. Find the distance between the two men.

Answer is 100√3m...=173.2m...U can solve this by taking a triangleABD..and by drawing an altitude on it...from A..to BD...name C...so AC=75m..and angle ABC=60degree and AngleADC=30degree..now use tan theta..in both the triangles to find...BC and CD..BC=75/√3 and CD=75*√3..so add both of them and U will get..100√3m(ans)..