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4 years later a father will be 8 years less than 3 times the age of his son.present age of father and son be x and y then write linear equation then find

Let age of father be x And age of son be y After four years Age of father will be x+4 Age of son will be y+4

According to the question x+4 = 3(y+4) - 8 ⇒ x+4 = 3y + 12 - 8 ⇒ x+4 = 3y + 4 ⇒ x+4 - 4 = 3y ⇒ x = 3y Given that son`s age = 10 yrs ⇒ y = 10 Father`s age = x = 3y ⇒ x = 3 ×10 ∴ x = 30 ∴ Age of father = 30 years