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Perimeter of a triangle ABC is 72 cm. Find the perimeter of the triangle DEF with vertices D,E and F as teh mid-points of the sides of the given triangle.



D and E are the midpoints of AB and BC respectively
therefore DE=1/2AC {MIDPOINT THEOREM}… similarly FE =1/2AB and DF=1/2BC .... DE+EF+FD=1/2(AB+CD+EF)=1/2*72cm=36cm
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