Answers

The Brainliest Answer!
2016-02-26T16:22:49+05:30
AT 1:00PM
=One bus leave
ANANDPUR to shivnagar
One bus leave average =45km/h
second bus leave average =40km/h
=Let the time =x
= time=45+
×t+40×t=225
= 85t=225
= t=3 hour
=1:00-4:00 PM
=anandpur speed to reach 4:00PM
=distance =time×speed
=d=3×45
=135 km away from anandpur
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