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A person on tour has RS. 4200 for his expenses. If he extends his tour for 3 days; he has to cut down his daily expenses by RS 70. Find the original

duration of the tour. this question is biting me for a long time. plz help. I will rate :)


Let the original duration of tour be x days
Amount with the person is Rs 4200
Daily expenses = Rs (4200/x)
Given tour extended for 3 more days
Hence total number of days = (x + 3) days
Daily expenses = Rs [4200/(x + 3)]
By the given problem, we have

(x + 15)(x – 12) = 0
Hence x = 12 as x cannot be negative
Thus the original duration of tour is 12 days.
1 5 1
after (by the given problem, we have) =4200/x-4200/x+3 =70                               4200(1/x-1/x+3)=70            60[(x+3-x)/x(x+3)]=1               180=x*x+3x           x*x+3x-180=0       x*x+15x-12x-180=0        x(x+15)-12(x+15)=0
plz mark as brailiest
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