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Given : ABCD is a parallelogram
To prove : ΔACD ≡ ΔACB

proof: In ΔACD and ΔACB
           AB = DC( opposite sides of a parallelogram are equal.)
            AC = AC(common)
           AD = CB (
opposite sides of a parallelogram are equal.)


so AC is the diagonal which divides the parallelogram in two congruent part
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