Answers

2016-02-22T15:47:25+05:30
I'm assuming that equation is equal to zero.
∴ 4x²-2x(a²+b²)+a²b² = 0
=> 4x²-2a²x-2b²x+a²b² = 0
=> 2x(2x-a²)-b²(2x-a²) = 0
=> (2x-a²)(2x-b²) = 0

=> 2x-a² = 0 OR 2x-b² = 0
=> x = a²/2 or b²/2
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