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## Answers

(x1+x2) =6*2

(x1+x2)=12

(x1+x2+x3)/3 =7

x1+x2+x3 =7*3

x1+x2+x3 =21

we know that value of x1+x2,

(x1+x2)+x3 =21

12+x3 =21

ie, x3 = 21-12 =9//

therefore the value of x3 is 9.

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(x1+x2) =6*2

(x1+x2)=12

(x1+x2+x3)/3 =7

x1+x2+x3 =7*3

x1+x2+x3 =21

we know that value of x1+x2,

(x1+x2)+x3 =21

12+x3 =21

ie, x3 = 21-12 =9//

therefore the value of x3 is 9.