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A carboxylic acid (molecular formula C2H4O2) reacts with an alcohol in the presence of an acid catalyst to form a compound ‘X’. The alcohol on oxidation

with alkaline KMnO4 followed by acidification gives the same carboxylic acid C2H4O2. Write the name and structure of (i) carboxylic acid, (ii) alcohol and (iii) the compound ‘X’.


1) CH3COOH and the structure will be as follows ,
=> H
H C - C =O
H \
2) The alcohol would be Ethyl Alcohol ,
=> C2H5OH
3) X compound is an ester ,
=> CH3COOC2H5 (Ethyl Methyl Ester or Ethyl Ethanoate )
0 0 0
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