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Two radii OA And OB of a circle are inclined at 120. Tangent are drawn at A and B to the circle to intersect at C. Show that ABC is equilateral triangle

Angle A and B are 90° angle 0 is 120° so angle C = 60°[sum of interior angles of a quadrilateral is 360°] now in triangle OAB OA=OB (radii) it means opp angles of these sides will be equal angle OAB=angle OBA = x x+x+angle O= 180°(ASP) 2x=180-angleO 2x= 180-120° 2x=60° x=30° now we know that AC=BC ( tangents) opp angles will be equal angle CAB=angleCBA angleOBC-angle OBA=angle CBA 90°-30°=60° angleCBA = angle CAB= angle ACB=60° in equilateral triangle all angles are of 60° as triangle ABC has so it proves it to be an equilateral triangle