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Three cubes of volume 64 cm 3 each are joined to the ends to form a solid.find the surface area of the cuboidso formed.with the steps plzz



It is given that the volume of each cube is 64cm3so basically a3= 64taking cube root a=4cmas there are 3 cubes joined end to endlength = 3*4= 12breadth= 4height = 4surface area of cuboid- 2(lb+bh+lh)= 2(4*12=4*4=4*12)= 2(48+16+48)=2(112)= 224cm2
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