Lol, I don't think that table matters at all.

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Lol, I don't think that table matters at all.

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No. of preferred possibilities = (4,5,6) = 3

∴ P(greater than 3) = 3/6 = 1/2 or 50% chance.

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This is because of the last line, which says that the die was tossed another time, in which case the previous results would not affect it.

But if that weren't there, and it only asked for the probabilities of the previous results,

*(which is think is what they intended)

probability of getting 4 = 149/1000

probability of getting 5 = 175/1000

probability of getting 6 = 190/1000

∴ probability of getting above 3 = (149+175+190)/1000 = 514/1000 =

3/6 which can also simplified as 1/2 or 50%