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A is younger than B and A is older than C A/q (age of A) - (age of C) = (age of B) - (age of A) ⇒2A = B +C and B+C = 48______(given) so, 2A = 48 age of A = 24 years

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Given A is younger than B as he is elder than C. Let the difference between the age of A and B and A and C which is equal be 'y'. Now,A=B-y and A=C+y Now A=B-y therefore,y=B-A,which is the L.H.S Now A=C+y Therefore ,y=A-C,which is the R.H.S Now,L.H.S-R.H.S ie;y-y=(B-A)-(A-C) 0=B-A-A+C 0=B+C-A-A 0=48-2A ie;48=2A Therefore A=48/2 =24.