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∆PQR is right angled at Q. A and B are the mid-points of sides PQ and PR respectively. If PQ=10 cm and PR=26 cm, then find the length of AB



OK so by using the mid point theorem...AB=1/2QR and also AB||QR..so Angle PAB=90°(alternate angles)..so in Triangle PAB..PA=10/2=5cm and PB=26/2=13cm..so by using Pythagoras theorem=>AB^2=PB^2-PA^2=169-25=144=AB^2... so AB=12cm(ans)
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