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2014-07-27T16:10:04+05:30

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16 g  = 1/2 mole of O2                       4 g =  2 mole of H2
     V = volume = 1 d / m^3        T = 27 C = 300 K
 
 P V = n R T          =>  P1  V  +  P2 V  = n1 R T  + n2 R T
                                      P1 is due to n1 moles O2  and P2 is due to n2 moles of H2 
P1 + P2 =  (RT/V) (n1+n2) =    (0.083 dm3  * 300 / 1 dm^-3 ) 2.5
             = 62.25 bar
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