Answers

2016-02-25T17:52:50+05:30
Since,
Na2 CO3 ⇒ Na2O +CO2
THUS .1 mole of Na2CO3 =  1 mole of CO2
i.e. 102.98 g of Na2 CO3 =44g of CO2
9.85 g of Na 2 CO3 =44/105.98*9.85
                               =4.0894g  of CO2
 no. of  mole of co2 produce=4.0894/44
                                                  = 0.0929 moles 
1 mole of co2  gas = 22.4 L
0.0929 mole of gas at STP = 22.4*0.0929L 
                                          =2.0809L of CO2 would be obtained .
hope its help ful  ...:)
 
































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