Answers

2016-02-25T18:07:31+05:30
In the cyclic quadilateral ABCD 
 let angle ADC be x now angle ABC is 180-x 
since AD is parallel to BC 
therefore angle ADC+angleDAB is 180 
angle DAB is 180-x 
now angle DAB and ABC r equal 
so AB=CD

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I think its not let me look to it again as soon as I get it right i'll edit it :)
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I think its not let me look to it again as soon as I get it right i'll edit it :)
this is the right way
ok
2016-02-25T18:17:02+05:30
Let ADC=x
So, abc=180-x
Since ad//bc
Bcd=abc=90
Adc=bad=90
So.ab=dc
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