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Let no. be x
As per question,

x+(1/x) = 61/30
=> 30(x
²+1) = 61x
=> 30x²+30-61x = 0

On solving this quadratic equation using Sridharacharya's method, we get,
x = 1.2 or 
1 5 1
wht s sridharacharyas method
It's really painful to type... It would be better if you looked it up
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