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In the below figure, ABCD is a parallelogram in which P and Q are mid-points of opposite sides AB and CD. If AQ intersects DP at S abd BQ intersects CP at

R, show that:
(i) APCQ is a parallelogram
(ii) DPBQ is a parallelogram
(iii) PSQR is a parallelogram

diagram plse
i would solve it if u post the diagram.



(i) In quadrilateral APCQ,

AP || QC        (Since AB || CD)        (1)

         AP = ½AB, CQ = ½CD     (Given)

Also,         AB = CD (Why?)

So,          AP = QC         (2)

Therefore, APCQ is a parallelogram [From (1) and (2) and Theorem 8.8]

(ii) Similarly, quadrilateral DPBQ is a parallelogram, because

         DQ || PB and DQ = PB.

(iii) In quadrilateral PSQR,

         SP || QR (SP is a part of DP and QR is a part of QB)

Similarly,        SQ || PR

So, PSQR is a parallelogram.

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