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Draw a line segment AB of 11 cm Construct 30° from A and 90° from B Construct angle bisectors for both the angles They will meet at X Construct perpendicular line bisector for AX and BX . The both lines will meet AB at X and Y Join XY and XZ XYZ is our required triangle.

Step 1: A line segment AB= 11 cm is drawn. (XY + YZ + ZX = 11 cm) Step 2: An angle, ∠A= 30° is constructed at point A and an angle ∠B = 90° at point B. Step 3: ∠A and ∠B are bisected . The bisectors of these angles intersect each other at point X. Step 4: Perpendicular bisectors TS of AX and ZU of BX are constructed. Step V: Let TS intersect ABat Y and ZU intersect AB at Z. XY and XZ are joined. Thus, ΔXYZ is the required triangle.