Answers

2016-02-26T14:35:42+05:30
Atomic weight of C4H10  = 58g
no. of mole of C4H10 = 29/58 = 1/2 mole
for 1 mole of butane combustion 9/2 mole of oxygen is required
for 1/2 mole of butane combustion 9/4 mole of oxygen is required
weight of oxygen = 9*16/4 = 36 gm.
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2016-02-26T20:09:52+05:30
ATOMIC MASS OF C4H10= 58g
NO OF MOLECULES =29/58 = 1/2 MOLECULES
           
        FOR 1 MOLECULE OBF BUTANE COMBUSTION 9/2 MOLECLES O2 IS RQD
       W OF O2 IS=9*16/4=36G
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