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In Δabd and Δbdc,
        BD is common
        ∠DAB =∠BCD=90°
        AB=DC (opp. sides in a rectangle)
         by RHS congruency,
         Δabd is congruent to Δbcd
      Then their areas are equal so,ar(abd)=ar(bcd)
     therefore ar(bcd)=8 cm sq.

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