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Water is flowing at 7m/s through a circular pipe of internal diameter of 2cm into cylindrical tank,the radius of whose base is 40cm. Find the increase in

water level in 30 minutes.


Water is flowing at the rate of 7 m/s.
o length of pipe in which the water has traveled,
h = 7(1800) = 12600m
Radius of the pipe(r)= 1cm
Radius of the cylinder(R)= 40 cm

let the height of the water in the tank H
Volume of water coming from the pipe = Volume of water in the cylindrical tank.

πr^2h = πR^2h
H = {(0.01)^2 X 12600}/(0.4)^2 = 7.875m (ans)

0 0 0
Here to find the height You should put the formula V. of cylindrical tank = Area of cross section x Speed of flowing water x time

rate of flow =7m s- for pipe:
radius = 1cm or 0.01m for tank :
 radius = 40cm or 0.4m time = 1/2hr = 30min =1800sec according to formula area of cross section = area of pipe *speed * time
pi r2h = pi R2 * 7*4800
h = 0.01*0.01*7*1800/0.4*0.4
h= 7.875
2 4 2
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