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Water is flowing at 7m/s through a circular pipe of internal diameter of 2cm into cylindrical tank,the radius of whose base is 40cm. Find the increase in

Water is flowing at the rate of 7 m/s. o length of pipe in which the water has traveled, h = 7(1800) = 12600m Radius of the pipe(r)= 1cm Radius of the cylinder(R)= 40 cm let the height of the water in the tank H So, Volume of water coming from the pipe = Volume of water in the cylindrical tank.

πr^2h = πR^2h H = {(0.01)^2 X 12600}/(0.4)^2 = 7.875m (ans)

Here to find the height You should put the formula V. of cylindrical tank = Area of cross section x Speed of flowing water x time

rate of flow =7m s- for pipe: radius = 1cm or 0.01m for tank : radius = 40cm or 0.4m time = 1/2hr = 30min =1800sec according to formula area of cross section = area of pipe *speed * time pi r2h = pi R2 * 7*4800 h = 0.01*0.01*7*1800/0.4*0.4 h= 7.875