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A balloon starts rising from ground from rest with an upward acceleration 2 m/s2. Just after 1 second, a stone is dropped from it. The time taken by stone

to strike the ground is nearly?


The balloon starts to rise vertically upward with an acceleration of 2m/s^{2}
After one second (First Case)
Therefore in this case; u = 0 ; t =1; a=2
The distance traveled in this case by the formula s=ut+ \frac{1}{2}at^{2}
∴ s = 1m
Case Two:-
From there a stone was dropped...
Therefore the stone was falling under the effect of gravity
Therefore in this case; u=0;s=1;a=9.8
The time can be calculated in this case by the formula s=ut+ \frac{1}{2}at^{2}
∴ t ≈ 0.45s
0 0 0
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