Answers

2016-02-27T21:35:59+05:30
Proof
AB=AD(GIVEN)
AC=AC(COMMON)
BC=CD(GIVEN THAT BC IS BISECTED)

by SSS congruence rule
ABC is congruent to ADC
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2016-02-28T07:38:10+05:30
FROM ΔABC and ΔACD

AB = AD (GIVEN)

AC = AC (COMMON)

BC = CD (AC BISECTS BD)

by SSS congruence 

ΔABC ≡ ΔACD
                               hence proved
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