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An object of height 2 cm is kept in front of a convex lens which produces magnification of 0.5. Calculate the size of the image, will the image be erect or

inverted. Why?


Inverted 100%
m=h/h' (h' = $ize of IMG)
h'= 4 cm
as m= positive
for more info click on crown ....**:). .............

IMG will formed
behind mirror it would be virtual
as a result IMG will be erect 100 ℅
0 0 0
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