Answers

2016-02-28T16:21:39+05:30
X⁴-y⁴+x²-y²
=> (x²+y²)(x²-y²)+(x²-y²)
=> (x²-y²)[(x²+y²)+1]
=> (x+y)(x-y)(x²+y²+1) should be the fully factorized form.
0
:)
btw, refer previous year's q.papers
okayy...
bye..
bii
2016-02-28T20:35:49+05:30
= (x² + y²)(x²-y²)+(x²-y²)
= (x²-y²)[(x²+ y²) +1 ]
= (x+y)(x-y)(x²+y²+1)
0