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Two forces whose magnitudes are in ratio 3:5 give a resultant equal to 49N, if the angle of inclination is 60 degree, find the magnitude of each force



Let the two forces are p and q then 
p/q = 3/5
according to question 
49 = √(p²+q²+2*p*q*cos60)
49 = √(9q²/25+q²+q²/5)
49 = 7q/5
q = 35N
p = 21N 
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