Answers

2016-03-01T16:55:45+05:30

Its ph will be 13. SOLUTION:  Ba(OH)2 - Ba2+  + 2OH-

0.05 M X 2= 0.10M   pOH= -log(0.10 M) = 1.00

pH = 14-pOH= 14 - 1.00=13


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