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In parallelogram ABCD,point E divides side AB in the ratio of 2:3 and EF is drawn parallel to side AD. The ratio of the areas of parallelogram AEFD to

parallelogram BEFC is?



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Let the length of AB be 'x'
then the length of AE =2x/5
& BE = 3x/5
area of parallelogram=lxb
area(AEFD)= AExAD=>2x/5*AD                                  (1)
area(BEFC)= BExAD=>3x/5*AD                                  (2)
ratio of (1)to(2)=2x/5*AD
answer is 2:3
1 5 1
why have you divided the length with 5?
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