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PQRS is a parallelogram and PX bisects ∠P and RY bisects ∠R

To prove: PX║RY

Proof:∠P =∠R
in ΔPSX and RQY
PS =QR(sides of a ║gm)
∠S = ∠Q(opposite sides)
∠SPX = ∠YRQ (FROM 1)

 from  CPCT we get 
⇒PY = XR    (PQ-QY=SR-SX)
PY║XR        (as PQ ║SR)

∴PYRX is a parallelogram 

⇒PX║RY (opposite sides of a ║gm)
0 0 0
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