Answers

2016-03-02T11:09:03+05:30
Figure of this question is attached!!

Proof clearly
OP = OR (equal radii)
OQ = OQ (common)
PQ = RQ (equal chords)
OPQ =congruent= ORQ (by SSS)
∠PQO = ∠RQO (CPCT)
Therefore,
Q is the bisector of angle PQR
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2016-03-02T11:39:15+05:30
IN Δ POQ and ROQ
PQ =RQ 
OQ = OQ
OP = OR
⇒ΔPOQ = ΔROQ

by CPCT ∠PQO =∠ RQO
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