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Hi there! Have questions about your homework? At Brainly, there are 60 million students who want to help each other learn. Questions are usually answered in less than 10 minutes. Try it for yourself by posting a question! :D

1.AD=BC...opp. Sides of a parallelogram and BC=CE... Given Hence, AD=CE 2.in triangle ADF and triangle ECF, AD=CE... From 1 Ang.DAF=angFEC...alternate angles angAFD=angCFE...vertically opp. Hence, ADF is congruent to ECF Hence arADF=arCFE 3.DF=FC...CPCT 4.triangle DBF lies on half the base DC of parallelogram ABCD and they lie between the same parallels AB and DC Hence arDFB=half(half(arABCD))... The area of triangle is half the area of parallelogram if they lie on Same base and between same parallels Hence, arDBF=0.25arABCD Hence arABCD=3*4=12cm^2
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