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Since, ABC and ADC are 2 right angle triangles with common hypotenuse AC then the right angles are also equal. If we draw a circle passing through ABCD with AC as the diameter. then it is ABCD will be cyclic

So DC will be the chord of the circle and angle CAD and angle CBD will be the angles subtended by the chord on the circumference of the circle. From the theorem of angles in the same segment are equal it is proved that angle CAD is equal to angle CBD