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Assume that the electron in Li2+ ion is in third orbit.calculate 1.the radius of the orbit,2.the total energy of electron (hint:Li2+ ion also had atomic

spectra similar to hydrogen atom.while applying relevant equations use Z=3)



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Radius in nth orbit =0.529Xn²/z. R=0.529X9/3=1.56A. Total energy =-13.6Xz²/n². Total energy=13.6X9/9=-13.6eV
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