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A particle moves in a straight line under constant acceleration of 4m/s^2. If its velocity at t=0 is 10m/s, the displacement of the particle in the 5th

second of its motion is

plz also show the procedure of doing the problem also.



As the acceleration is positive and particle is moving in a straight so displacement and distance are equal 
u = =10m/s
distance travel in 5th second = 10 + (2*5-1)*4/2
                                          = 28 m
so displacement of particle = 28m.
0 0 0
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