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If an employee walks at 2/3 of his usual speed, he gets late to the office by 15 mins. What time does he usually take to reach the office? A. 10 min. B. 30

min C. 35 min, D. 25 min


Answer is 30 minutes....

Let original speed be x and original time taken be t
let d be the distance 
Speed = d/t

if speed be 2x/3 time will be t+15

2x/3 = d/(t+15)
2(d/t)/3 = d/(t-+15)
2/3t = 1/(t+15)

Cross multiply

2(t+15) = 3t
2t+30 = 3t
3t-2t = 30
t = 30..............(answer)

Hope it is correct

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