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From the tower, 100m high, a man observes two cars on the opposite sides of the tower with the angles of depression 30 degree and 45 degree respectively.

Find the distance between the cars. ( use pi = 22/7 )

Given that AB is the distance between the to cars CD is the height of the tower = 100m the angle of depression is 45 and 30 from ΔADC tan45 = cd/ad 1 = 100/ad ad = 100m

from ΔBDC tan30= cd/bd 1/√3 = 100/bd bd = 100√3 the distance of the cars = BD+AD = 100√3+100 = 173.2 +100 = 273.2m