Answers

2016-03-05T15:04:35+05:30

Here ,

O is the center and from O we have drawn a perpendicular bisector of CD

We have to prove that AB < CD

Draw ON perpendicular to CD

So OME is a right angled triangle

And ,

OM is the hypotenuse so ,

OM>OE

Therefore chord CD is nearer to O in comparison to AB

Therefore,

CD>AB

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