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Lead spheres of diameter 6 cm each are dropped into a cylindrical beaker containing some water and are fully submerged. If the diameter of the beaker is 18

cm and water level rises by 40 cm, find the number of lead spheres dropped in the water.


V1= 4/3π(6)³
V2/V1 = no. of balls
= (9×9×40)÷(4×2×6×6)
= 3240/288= 11.25=11(approx)
= no.of balls
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